1.

In a given process on an ideal gas dW = 0 and dQ angle 0. Then for the gas :

Answer»

the volume will increase
the temperature will increase
the PRESSURE will remain constant
the temperature will decrease.

Solution :As `dQ LT 0 and dW=0`
`& dQ =dU+dW`
CHANGE in internal energy `dU lt 0`
`rArr` Internal energy decreases and hence temperature also decreases.
Thus, CORRECT choice is (a).


Discussion

No Comment Found

Related InterviewSolutions