1.

In a given process on an ideal gas, dW = 0 " and " dQ lt 0. Then for the gas

Answer»

the temperature will DECREASE
the volume will increase
the PRESSURE will remain CONSTANT
the temperature will increase.

Solution :`dU = dQ - dW rArr dU = dQ - 0 = dQ`
But as per question, `dQ lt 1`
` :. dU lt 1`
` :. ` The temperature will decrease.


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