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In a gravimetric determination of phosphorus 0.24 gr of an organic compound was strongly heated in carius tube with conc nitric acid. Phosphoric acid so produced was precipitated as MgNH_(4)PO_(4) which on ignition yielded 0.444 gr of Mg_(2)P_(2)O_(7) the percentage of phosphorus in the compound is ........... x 10 [Mg = 24, P = 31, O = 16]

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SOLUTION :`%P=(62 xx "Wt of" Mg_(2)P_(2)O_(7) xx 100)/(222 xx "Wt of ORGANIC compound")=50%`


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