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In a horizontal oil pipeline of constant cross-sectional area the pressure decrease between two point 300 km apart is 5000 pascal (1 pascal = 1 newton per square meter). What is the loss of energy per unit volume per unit distance? [Hint : Loss in energy `=(P_(1))/(rho)-(P_(2))/(rho)` because `(P)/(rho)` is pressure energy per unit mass and loss in energy per unti volume `=P_(1)-P_(2)`.] |
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Answer» Correct Answer - `0.01667`J |
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