Saved Bookmarks
| 1. |
In a hydrogen atom, the electron revolves round the nucleus 6.8 xx 10^(15) times per second in an orbit of radius 0.53Å. What is equivalent magnetic moment ? (Given that e=1.6 xx 10^(-19)C). |
|
Answer» Solution :The electron revolving in an ORBIT is EQUIVALENT to a current loop. The magnitudeto current is given by , `I =(e)/(T) = e xx (1)/(T) = ef= (1.6 xx 10^(-19)) (6.8 xx 10^(15))` `=1.1 xx 10^(-3) A ` Magnetic MOMENT of equivalent current loop is M= nIA . Here `n=1 ,I = 1.1 xx 10^(-3) A` and AREA ,`A = pi ( 0.53 xx 10^(-10))^(2)` `:. M = (1)(1.1 xx 10^(-3)) [ pi (0.53 xx 10^(-10))^(2)]` `=9.7 xx 10^(-24) Am^(2)` |
|