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In a hydrogen atom, the radius of n^(th) bohr orbit is r_n. The graph between log (r_n//r_1) and logn will be |
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Answer»
So, LOG `(r_n//r_1)=21`OGN Hence, the GRAPH between log `(r_n//r_1)` and logn will be a straight line passing through origin. The POSITIVE SLOPE is given by `tantheta=2`. |
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