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In a hydrogen atom, the radius of n^(th) bohr orbit is r_n. The graph between log (r_n//r_1) and logn will be

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Solution :we know that `r_npropn^2` or `(r_n//r_1)=n^2`
So, LOG `(r_n//r_1)=21`OGN
Hence, the GRAPH between log `(r_n//r_1)` and logn will be a straight line passing through origin.
The POSITIVE SLOPE is given by `tantheta=2`.


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