1.

In a hydrogen atom, the transitiontakes place from n = 3to n = 2 . If Rydberg constant is 1.097 xx 10^(7) m^(-10. The wavelengthof the emiited radiation is

Answer»

`(36)/(5R_(H))`
`(5R_(H))/(36)`
`(3)/(4R_(H))`
`(4)/(3R_(H))`

SOLUTION :`1/lambda = R_(11)Z^(2)[1/(n_(1)^(2))-(1)/(n_(2)^(2))]`
`1/lambda=R_(11)XX(1)^(2)[1/4-1/9]`
`1/lambda=R_(11)[5/36]`
`=lambda=(36)/(5R_(11))`


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