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In a hydrogen like atom electron make transition from an energy level with quantum number `n` to another with quantum number `(n - 1)` if `n gtgt1` , the frequency of radiation emitted is proportional to :A. `(1)/(n)`B. `(1)/(n^(2))`C. `(1)/(n^(3)2)`D. `(1)/(n^(3)2)` |
Answer» Correct Answer - B::D `DeltaE=hv` `v=(DeltaE)/(h)=k[(1)/((n-1)^(2))-(1)/(n^(2))]=(k2n)/(n^(2)(n-1)^(2))` `~~(2K)/(n^(3))prop(1)/(n^(3))` `r=(mv)/(eB)rArr(r^(2)e^(2)B^(2))/(2)=(m^(2)v^(2))/(2)` `(r^(2)e^(2)B^(2))/(2m)=(mv^(2))/(2)` `1.89-phi=(r^(2)e^(2)B^(2)1)/(2m)(1)/(e)eV=(r^(2)eB^(2))/(2m)eV=(100xx10^(-6)xx1.6xx10^(-19)xx9xx10^(-8))/(2xx9.1xx10^(-31))` `phi=1.89-(1.6xx9)/(2xx9.1)` `=1.89=0.79~=1.1 eV` |
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