Saved Bookmarks
| 1. |
In a large bullding there are 15 bulbs of 40 W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of the electric mains is 220 V. The minimum capacity of the main fuse of the building will be : |
|
Answer» `12 `A Total power = 40 `xx 15 + 100 xx 5 + 80 xx 5 + 1000` = `600 + 500 + 400 + 1000 ` `therefore VI = 2500` W `therefore I = (2500)/(220) = 11.36`A `therefore I = 12 A ` |
|