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In a `LCR` circuit having `L=8.0` henry, `C=0.5 mu F` and `R=100` ohm in series. The resonance frequency in per second isA. `600` radianB. `600 Hz`C. `500` radianD. `500 Hz` |
Answer» Correct Answer - C Resonance frequency in radian/second is `omega=1/(sqrt(LC))=1/(sqrt(8xx0.5xx10^(-6)))=500 rad//sec` |
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