In a lift moving up with an acceleration of 5 m s^(-2), a ball is dropped from a height of 1.25 m. The time taken by the ball to reach the floor of the lift is ……(nearly) (g = 10 ms^(-2))

In a lift moving up with an acceleration of 5 m s^(-2), a ball is drop

1.	In a lift moving up with an acceleration of 5 m s^(-2), a ball is dropped from a height of 1.25 m. The time taken by the ball to reach the floor of the lift is ……(nearly) (g = 10 ms^(-2))
Answer» 0.3 second 0.2 second 0.16 second 0.4 second Solution :SINCE life is ascending upward with acceleration a. So when the ball is dropped then it WELL fall with an acceleration of g+a i.e 10+5 =`15m//s^(2)` `:.` TIME of descnt is `T=sqrt((2h)/(g+a))=sqrt((2xx1.5)/(15))=0.4s`

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In a lift moving up with an acceleration of 5 m s^(-2), a ball is dropped from a height of 1.25 m. The time taken by the ball to reach the floor of the lift is ……(nearly) (g = 10 ms^(-2))

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