In a lottery, a person chooses six different numbers at random from 1

1.	In a lottery, a person chooses six different numbers at random from 1 to 20, and if these six numbers match with six numbers already fixed by the lottery committee, he wins the prize. What is the probability of winning the prize in the game?
Answer» given: six numbers are chosen from 1-20 Formula: P(E) = \(\frac{favorable\ outcomes}{total\ possible\ outcomes}\) we have to find the probability of winning the prize total possible outcomes of selecting six numbers from 1-20 is ²⁰C₆ therefore n(S)= ²⁰C₆= 38760 let E be the event that all six numbers match with the given number (as winning number is fixed) n(E)=1 probability of occurrence of the event is P(E) = \(\frac{n(E)}{n(S)}\) P(E) = \(\frac{1}{38760}\)

In a lottery, a person chooses six different numbers at random from 1 to 20, and if these six numbers match with six numbers already fixed by the lottery committee, he wins the prize. What is the probability of winning the prize in the game?

Answer»

given: six numbers are chosen from 1-20

Formula: P(E) = \(\frac{favorable\ outcomes}{total\ possible\ outcomes}\)

we have to find the probability of winning the prize

total possible outcomes of selecting six numbers from 1-20 is ²⁰C₆

therefore n(S)= ²⁰C₆= 38760

let E be the event that all six numbers match with the given number (as winning number is fixed)

n(E)=1

probability of occurrence of the event is

P(E) = \(\frac{n(E)}{n(S)}\)

P(E) = \(\frac{1}{38760}\)

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In a lottery, a person chooses six different numbers at random from 1 to 20, and if these six numbers match with six numbers already fixed by the lottery committee, he wins the prize. What is the probability of winning the prize in the game?

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