1.

In a meter bridge with a standard resistanceof 15Omega in the right gap, the ratio of balancing length is 3:2. Find the value of the other resistance.

Answer»

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SOLUTION :`Q=15Omega, l_(1):l_(2)=3:2`
`(l_(1))/(l_(2))=(3)/(2)`
`(P)/(Q)=(l_(1))/(l_(2)) rArr P=Q(l_(1))/(l_(2))`
`P=15(3)/(2)=22.5Omega`


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