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In a meter bridge with a standard resistanceof 15Omega in the right gap, the ratio of balancing length is 3:2. Find the value of the other resistance. |
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Answer» <P> SOLUTION :`Q=15Omega, l_(1):l_(2)=3:2``(l_(1))/(l_(2))=(3)/(2)` `(P)/(Q)=(l_(1))/(l_(2)) rArr P=Q(l_(1))/(l_(2))` `P=15(3)/(2)=22.5Omega` |
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