InterviewSolution
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InterviewSolution
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In a metre bridge the null point is found at a distance of 35 cm from A. If now a resistance of 10Omega is connected in parallel with S, the null point occurs at 50 cm. Determine the values of R and S. |
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Answer» Solution :From the first balance point, we get `(R)/(S)`=`(35)/(65)`=`(7)/(13)`…….(1) After S is connected in parallel with a resistance of `10Omega`, the resistance across the gap CHANGES from S to`S_(EQ)`where `S_(eq)`=`(10xxS)/(10+S)` and hence the new balance condition now gives `(R)/(S_(eq))`=`(R(S+10))/(10S)`=`(50)/(50)`=1….(2) by EQUATION (1) & (2) we get S=`(60)/(7)Omega`, R=`4(8)/(13)Omega` |
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