1.

In a mixture, two enantiomers are found to be present in 85% and 15% respectively. The enatiomeric excess (e,e) is

Answer»

0.85
0.15
0.7
0.6

Solution :Since the TWO enantiomers are present in 85% and 15% RESPECTIVELY, therefore, 15% out of 85% will form a racemic mixture with the other ISOMER. Therefore, enantiomeric excess `(e,e)=85-15=70%`


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