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In a morning walk, 3 persons step off together, their steps measuring 40 cm, 45 cm and 50 cm respectively. What is the minimum distance each should walk so that he can cover the distance in complete steps. |
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Answer» The minimum distance that they all three should walk will be the L.C.M. of 40, 45, 50. Since 40=2×2×2×5 45=3×3×5 50=2×5×5 ∴ L.C.M. of 40, 45 and 50 = 2×2×2×3×3×5×5= 1800cm = 18m |
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