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    				| 1. | 
                                    In a n-p-n transistor, the collector current is 10 mA . If 90%the electrons emitted reach the collector. | 
                            
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Answer»  the emitter current will be9mA `=(90)/100 I_e=9/10 I_e:. I_e=10/9I_c` . `=10/9xx10=11.1 mA` Now `I_b=I_e -I_c = 11.1 -10=0.1mA`  | 
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