1.

In a n-p-n transistor, the collector current is 10 mA . If 90%the electrons emitted reach the collector.

Answer»

the emitter current will be9mA
the emitter current will be 11 mA
the BASE current will be 1mA
the base current will be0.1 mA.

Solution :`I_c=90%" of "I_e`
`=(90)/100 I_e=9/10 I_e:. I_e=10/9I_c` .
`=10/9xx10=11.1 mA`
Now `I_b=I_e -I_c = 11.1 -10=0.1mA`


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