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In a noiseless transformer, an alternating current of 2A is flowing in primary coil. The number of turns in primary and secondary coil are 100 and 20 respectively the secondary current is ......... |
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Answer» Solution :`I_1`=2A , `N_1` = 100, `N_2`= 20 , `I_2`= ? `I_2/I_1=N_1/N_2` `therefore I_2=I_1 N_1/N_2 = (2xx100)/20`= 10 A |
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