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In a p-n junction diode, the depletion region is 400 nm wide and an electric field of 5xx10^(5)V//m exists in it. The minimum kinetic energy of a conduction electron which can diffuse from n side to p side is |
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Answer» Solution :The p.d ACROSS the junction V = Ed But change in K.E. = work done `therefore` the K.E required to CONDUCT electron from n SIDE to p side = V electron VOLTS `5xx10^(5)xx400xx10^(-9)=0.2eV` |
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