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In a p-n junction diode, the depletion region is 400 nm wide and an electric field of 5 xx 10^5 V//m exists in it. The minimum kinetic energy of a conduction electron which can diffuse from n side to p side is |
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Answer» Solution :The p.d across the JUNCTION V = ED But change in K.E. = work done `therefore ` the K.E REQUIRED to conduct electron from n side TOP side = V electron volts ` = 5 xx 10^5 xx 400 xx 10^(-9) = 0.2eV ` |
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