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In a p-n junction, width of depletion region is 300 nm and electric field of 7 xx 10^(5) V//m exists in it. (i) Find the height of potential barrier. (ii) What should be the minimum kinetic energy of a conduction electron which can diffuse from the n-side to the p-side? |
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Answer» SOLUTION :(i) `V=Ed = 7 xx 10^(5) xx 300 xx 10^(-9)= 0.21 V` (ii) KINETIC energy =EV = 0.21 eV |
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