1.

In a p-n junction, width of depletion region is 300 nm and electric field of 7 xx 10^(5) V//m exists in it. (i) Find the height of potential barrier. (ii) What should be the minimum kinetic energy of a conduction electron which can diffuse from the n-side to the p-side?

Answer»

SOLUTION :(i) `V=Ed = 7 xx 10^(5) xx 300 xx 10^(-9)= 0.21 V`
(ii) KINETIC energy =EV = 0.21 eV


Discussion

No Comment Found

Related InterviewSolutions