1.

In a parallel plate capacitor the potential difference of 100 V is manitianed between the plates. If distance between the plates be 5mm, what will be the electric field at points A and B ?

Answer»

Solution :ELECTRIC field at both paints A and B is same having a value
`E = V/d = (100 V)/(5mm) = (100 V)/(5 xx 10^(-3)m) = 2 xx 10^4 NC^(-1)`


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