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In a parallel plate capacitor with air between the plates, each has an area 8xx10^(-3)m^(2) and distance between the plates is 2 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 50 V supply, what is the charge on each plate of the capacitor? (Absolute permittivity of free space =8.85xx10^(-12)Fm^(-1)) |
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Answer» Solution :Given `A=8xx10^(-3) m^2, d=2xx10^(-3)`m `C_"air"`=? V=50 V , Q=? `e_0=8.85xx10^(-2) Fm^(-1)`  WKT electricalcapacitanceof an air CAPACITOR `C=(epsilon_0A)/d` i.e.,`C=(8.85xx10^(-2) xx8xx10^(-3))/(2xx10^(-3))` i.e.,`C=35.416xx10^(-2)` (farad) Also, WKT Q=chargean the capacitor =CV i.e.,`Q=35.416xx10^(-12)xx50` `=1770.8xx10^(-12)` C `Q=1.771xx10^(-9)` C(Coulomb ) |
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