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In a parallelogram ABCD, P is any point on the side AB. A line AQ drawn parallel to PC, intersects DC at Q. BD intersects AQ at S and PC at R. Prove that ar(ΔPRB)=ar(ΔDSQ)

Answer» In a parallelogram ABCD, P is any point on the side AB. A line AQ drawn parallel to PC, intersects DC at Q. BD intersects AQ at S and PC at R. Prove that ar(ΔPRB)=ar(ΔDSQ)


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