

InterviewSolution
Saved Bookmarks
1. |
In a parallelogram ABCD, the side DC is produced to E and ∠BCE = 105° calculate ∠A,∠E,∠C and∠D. |
Answer» ∠DCB + ∠DCE = 180° [Linear pair] ∠DCB + 105° = 180° ∠DCB = 180° – 105° ∠DCB = 75° ∠A = ∠DCB = 75° ∠A =∠C = 75° [Opposite angles of a parallelogram] ∠A +∠B = 180° [adjacent angles of a parallelogram] 75° +∠B = 180° ∠B = 180° + 75° ∠B = 105° ∠B = ∠D = 105° [Opposite angles of a parallelogram] |
|