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In a parallelogram ABCD whose vertices are taken in order, if ∠A=40°∠A=40° , then ∠D=​

Answer»

a PARALLELOGRAM Given ∠DAB=∠BCD=40 0 and AD∥BCWe know that SUM of consecutive angle are 180 0 ∠CBA+∠DAB=180 0 ∴∠CBA=180−40=140 0 We know that in parallelogram opposite angles are equalThen ∠ADC=∠CBA=140 0 So angles of parallelogram are 40 0 ,140 0 ,40 0 ,140 0



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