1.

In a particular experiment , 272 g of phosphorus, P_(4) , reacted withexcess ofoxygen of form P_(4)O in89 . 5 %yield. In the secondstep of thereaction, a 97.8%yield of H_(3) PO_(4) was obtained. Whatmassof H_(3) PO_(4) was obtained ?

Answer»

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Solution :ApplyingPOAC for P atomsfor the followingsteps. In the firststep, for `89.5%` yield,
moles of `P_(4) O_(10)` produced = moles of `P_(4) xx 0.895`
`= (272)/(124) xx 0.895 = 1.9632`
In the SECOND STEP,for `97.8% ` yield,
moles of `H_(3) PO_(4)` produced ` = 4 xx ` moles of `P_(4) O_(10) xx 0.978`
`= 4 xx 1.9632 xx 0.978 = 7.680`
`:.`wt. of `H_(3) PO_(4)` produced = `7 . 680 xx 98 g`
= 752 . 65 g


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