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In a particular reduction process, the concentration of a solution that is initially 0.24 M is reduced to 0.12 M in 10 hours and 0.06 M in 20 hours. What is the rate constant of this reaction ?

Answer»


Solution :As `t_(1//2)` is independent of INITIAL CONCENTRATION, it is a reaction of 1ST ORDER. `t_(1//2)=10` hours,
`k=0.693//t_(1//2)=0.693//10" hr"=6.93xx10^(-2)hr^(-1)" or "0.693//(10xx3600)s^(-1)=1.9xx10^(-5)s^(-1).`


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