In a particular reduction process, the concentration of a solution that is initially 0.24 M is reduced to 0.12 M in 10 hours and 0.06 M in 20 hours. What is the rate constant for the reaction?

In a particular reduction process, the concentration of a solution tha

1.	In a particular reduction process, the concentration of a solution that is initially 0.24 M is reduced to 0.12 M in 10 hours and 0.06 M in 20 hours. What is the rate constant for the reaction?
Answer» Let us calculate the rate constant (k) in both the cases. Ist case: a=0.24 M, (a-x)=0.24-0.12 = 0.12 M, t=10 hr For the first order reaction, `k=2.303/t log a/(a-x) = (2.303)/(10 hr) log (0.24M)/(0.12M) = 2.303/(10 hr) log 2=(2.303 xx 0.3010)/(10 hr)` `(0.693)/(10hr) = 0.693 hr^(-1) = 6.93 xx 10^(-2) hr^(-1)` IInd case: a=0.24 M, a-x =0.24-0.06=0.18M, t=20 hr. For the first order reaction, `k=(2.303)/t log a/(a-x) = 2.303/(20 hr) log (0.24 M)/(0.06 M) = (2.303)/(20 hr) log4 = (2.303)/(20 hr) xx 2 log 2` `=(2.303 xx 2 xx 0.3010)/(20 hr) = 0.0693 hr^(-1) = 6.93 xx 10^(-2) hr^(-1)`

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In a particular reduction process, the concentration of a solution that is initially 0.24 M is reduced to 0.12 M in 10 hours and 0.06 M in 20 hours. What is the rate constant for the reaction?

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