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In a pesudo first order hydrolysis of ester in water, the following results were obtained. {:("1",0,30,60,90),("[Ester]mol L"^(-1),0.55,0.31,0.17,0.085):} Calculate the average rate of reaction between the time interval 30 to 60 seconds. |
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Answer» Solution :AVERAGE rate of reaction between the time interval, 30 to 60 SECONDS `=("d[ESTER]")/(dt)` `=(0.31-0.17)/(60-30)=(0.14)/(30)` `=4.67xx10^(-3)"mol L"^(-1)s^(-1)`. |
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