Saved Bookmarks
| 1. |
In a photoelectric effect experiment , the maximum kinetic energy of the ejected photoelectrons is measured for various wavelength of the incident light. Figure shows a graph of this maximum kinetic energy K_(max) as a function of the wavelength lamda of the light falling on the surface of the metal. Which of the following statement/i is/ are correct? |
|
Answer» Threshold frequency for the metal is `1.2xx10^(15)m` Threshold frequncy, `v_0=(c)/(lamda_0)=(3xx10^(8))/(250xx10^(-9))HZ=1.2xx10^(15)Hz` Work function of the metal, `W=(hc)/(lamda_0)=(1242eVnm)/(250)=4.068eV` `(hc)/(lamda)=(hc)/(lamda_0)+K_(MAX)` `K_(max)=(1242eVnm)/(100nm)-4.968eV` `=7.432eVapprox7.4eV` Photoelectric effect takes placeonly for light of wavelength less than 250 nm, whereas `lamda_(red)approx700nm`. |
|