Saved Bookmarks
| 1. |
In A POR. M = 15. PO = 25PR = 20, NR - S.State whether lineNM is parallel to side RQ. Give |
|
Answer» Solution- By applying contradiction, we can prove that NM is parallel to RQ. Let's assume, NM || RQ Then, ΔPRQ ≈ ΔPNM, as ∠P is common to both the TRIANGLES ∠PNM = ∠PRQ (as corresponding angle of parallel lines) ∠PMN= ∠PQR (as corresponding angle of parallel lines) Applying SIMILAR triangle properties, \Rightarrow \frac{PN}{PR}=\frac{PM}{PQ} \Rightarrow \frac{PR-NR}{PR}=\frac{PM}{PQ} \Rightarrow \frac{20-8}{20}=\frac{15}{25} \Rightarrow \frac{12}{20}=\frac{15}{25} \Rightarrow \frac{3}{5}=\frac{3}{5} As the RATIOS came out to be same, so what we had assumed was correct. Therefore, NM || RQ.(Proved)Step-by-step explanation: |
|