In a potentiometer arrangement a cell of emf 1.25 V givesn a balance point at 35 cm length of the wire. If the cell is replaced by another cell and the balance point shift to 63 cm, what is the emf of the second cell ?

In a potentiometer arrangement a cell of emf 1.25 V givesn a balance p

1.	In a potentiometer arrangement a cell of emf 1.25 V givesn a balance point at 35 cm length of the wire. If the cell is replaced by another cell and the balance point shift to 63 cm, what is the emf of the second cell ?
Answer» Solution :Emf of the `"CELL"_(1), xi_(1)=1.25V` BALANCING length of the cell, `l_(1)=35cm=35xx10^(-2)m` Balancing length after interchanged, `l_(2)=63cm = 63xx10^(-2)m` Emf of the `"cell"_(2), xi_(2)=?` The RATIO of emf.s, `(xi_(1))/(xi_(2))=(l_(1))/(l_(2))` The ratio of emf.s, `xi_(2)=xi_(1)((l_(2))/(l_(1)))` `=1.25xx((63xx10^(-2))/(35xx10^(-2)))=12.5xx1.8` `xi_(2)=2.25V`

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In a potentiometer arrangement a cell of emf 1.25 V givesn a balance point at 35 cm length of the wire. If the cell is replaced by another cell and the balance point shift to 63 cm, what is the emf of the second cell ?

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