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In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 30.0 cm lengththe wire. If the cell is replaced by anotherand the balance point shifts to 60.0 cm, what the emf of the second cell ? |
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Answer» SOLUTION :In case of potentiometer ratio of two EMFS is, `(epsilon_(1))/(epsilon_(2)) = (l_(1))/(l_(2))` `therefore (1.25)/(epsilon_(2)) = (35)/(63)` `therefore epsilon_(2) = 1.25 XX (63)/(35)` ` therefore epsilon_(2) = 2.25 ` V |
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