In a potentiometer arrangement for determining the emf of a cell, the balance point of the cellin open circuit is 350 cm. When a resistance of 9Omegais used in the external circuit of the cell, thebalance point shifts to 300 cm. Determine the internal resistance of the cell.

In a potentiometer arrangement for determining the emf of a cell, the

1.	In a potentiometer arrangement for determining the emf of a cell, the balance point of the cellin open circuit is 350 cm. When a resistance of 9Omegais used in the external circuit of the cell, thebalance point shifts to 300 cm. Determine the internal resistance of the cell.
Answer» SOLUTION :Here balance point in open circuit `l_1` = 350 cm, balance point in CLOSED circuit` l_2`= 300 cm andexternal resistance R=9`OMEGA` ` therefore ` INTERNAL resistance of the cell`r = (l_1- l_2)/(l_2).R = (350 - 300)/(300) xx 9 = 1.5 Omega`

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In a potentiometer arrangement for determining the emf of a cell, the balance point of the cellin open circuit is 350 cm. When a resistance of 9Omegais used in the external circuit of the cell, thebalance point shifts to 300 cm. Determine the internal resistance of the cell.

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