1.

In a potentiometer experiment of a cell of emf 1.25 V gives balancing length of 30 cm. If the cell is replaced by another cell, balancing length is found to be 40 cm. What is the emf of second cell ?

Answer»

`~= 1.57 V`
`~= 1.67`
`~=1.47`
`~=1.37 V`

Solution :`E_(1) alpha l_(1)`
`E_(1)alpha l_(2)`
`(E_(1))/(E_(1)) = (l_(1))/(l_(2)) rArr (1.25)/(E_(2)) = (30)/(40) rArr E_(2) = (5)/(3) = 1.67 V`


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