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In a potentiometer experiment of a cell of emf 1.25 V gives balancing length of 30 cm. If the cell is replaced by another cell, balancing length is found to be 40 cm. What is the emf of second cell ? |
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Answer» `~= 1.57 V` `E_(1)alpha l_(2)` `(E_(1))/(E_(1)) = (l_(1))/(l_(2)) rArr (1.25)/(E_(2)) = (30)/(40) rArr E_(2) = (5)/(3) = 1.67 V` |
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