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In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10 Omega is connected in parallel to the cell, the balancing length changes by 60 cm . Find the internal resistance of the cell. |
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Answer» SOLUTION :`R= 10 Omega,` BALANCING length `l_1 = 560 CM` Change in balancing length `(l_1 - l_2) = 60 cm` internal resistance= r= ? `l_1 - l_2 = 60 , 56 - l_2 = 60` `therefore l_2 = 500 cm` `r= R((l_1 - l_2)/(l_2)) = 10 xx (60)/(500) = 6/5 = 1.2 Omega` |
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