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In a potentiometer experiment, the balancing point with a cell is at a length 240 cm. On shunting the cell with a resistance of 2 Omega, the balancing length becomes 120 cm. The internal resistance of the cell is |
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Answer» `1 Omega` `E-ir=E-(ER)/(2+r) =kl_(2) rArr E = kl_(2) [(2+r)/(2)]`...(ii) From eqn. (i) and (ii), `(2+r)/(2) = (l_(1))/(l_(2)) = (240)/(120)` `rArr r= 2OMEGA` |
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