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In a potentiometer experiment when a battery of e.m.f . 2 V is included in the secondary circuit, the balance point is at 500 cm . Find the balancing length from the same end when a cadmium cell is e.m.f 1.018V is connected to the secondary circuit. |
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Answer» Solution :e.m.f of first CELL `E_1 = 2V` e.m.f of second cell `E_2 = 1.018 V` First balancing length `l_1 = 500 cm` Let second balancing length =` l_2` `E prop l` `(E_1)/(E_2) = (l_1)/(l_2)` `l_2 = (E_2)/(E_1) xx l_1 = (1.018)/2 xx 500 = 254.5 cm` |
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