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In a process the pressure of a gas is inversely proportional to the square of the volume. If temperature of the gas increases, then work done by the gas:A. is positiveB. is negativeC. is zeroD. may be positive

Answer» Correct Answer - B
`P alpha (1)/(V^(2)) rArr P = (k)/(V^(2)) rArr PV^(2) = k`
`rArr PV. V = k rArr nRTV = k rarr TV = k_(1)`
Since temperature increases therefore volume decreases or work done by the gas is negative.


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