InterviewSolution
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InterviewSolution
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In a projectile motion, the maximum height reached equals to the horizontal range covered by the body, the angle of projection with the horizontal equals to |
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Answer» `tan^-1 1` HORIZONTAL Range = `(u^2 sin2 theta)/(g)` GIVEN `(u^2 sin^2 theta)/(2g)` = `(u^2 sin2 theta)/(g)` or `sintheta = 2 sin 2 theta` or `tantheta` = 4 or `theta tan^-1(4)`. |
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