In a pseudo first order hydrolysis of an ester in water, and following results were obtained: (i) Calculate the average rate of reaction between the time interval 30 to 60 seconds. (ii) Calculate the pseudo first order rate constant for the hydrolysis of ester.

In a pseudo first order hydrolysis of an ester in water, and following

1.	In a pseudo first order hydrolysis of an ester in water, and following results were obtained: (i) Calculate the average rate of reaction between the time interval 30 to 60 seconds. (ii) Calculate the pseudo first order rate constant for the hydrolysis of ester.
Answer» SOLUTION :(i) Average rate during the INTERVAL `30-60` seconds `=(C_(2)-C_(1))/(t_(2)-t_(1))=(0.31-0.17)/(60-30)=(0.14)/(30)" MOL L"^(-1)s^(-1)=4.67xx10^(-3)" mol L"^(-1)s^(-1)` (ii) `k=(2.303)/(t)"log"([A_(0)])/([A])` in which `[A_(0)]=0.55M` At t = 30 seconds, `k=(2.303)/(30s)"log"(0.55)/(0.31)=1.91xx10^(-2)s^(-1)` At t = 60 seconds,`k=(2.303)/(60S)"log" (0.55)/(0.17)=1.96xx10^(-2)s^(-1)` At t = 90 seconds, `k=(2.303)/(90s)"log"(0.55)/(0.085)=2.07xx10^(-2)s^(-1)` Average `k=(1.91+1.96+2.07)/(3)xx10^(-2)=1.98xx10^(-2)s^(-1)`.