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| 1. |
In a pseudo first order reaction of hydrolysis of an ester in H_2O, the following results were obtained : Calculate the average rate of reaction between the time interval 30 to60 sec. |
| Answer» Solution :AVERAGE RATE during 30-60 SEC. `=(0.17-0.31)/(60-30)=4.67xx10^(-3) "MOL L"^(-1) "sec"^(-1)` | |