In a quadrilateral ABCD a = x degree ,b= 60 +x degree , c = 60 degrees

1.	In a quadrilateral ABCD a = x degree ,b= 60 +x degree , c = 60 degrees=130 degrees (find x)
Answer» Answer: A = x° B = (60 + x)° C = 60° D = 130° A + B + C + D = 360° (Reason:- Angle SUM property of a quadrilateral : angles of a quadrilateral add UPTO 360°) x° + 60 + x° + 60° + 130° = 360° 2x° + 250° = 360° 2x° = (360 - 250)° 2x° = 110° x° = 110° 2 x° = 55°

In a quadrilateral ABCD a = x degree ,b= 60 +x degree , c = 60 degrees=130 degrees (find x)

Answer»

Answer:

A = x°

B = (60 + x)°

C = 60°

D = 130°

A + B + C + D = 360°

(Reason:- Angle SUM property of a quadrilateral : angles of a quadrilateral add UPTO 360°)

x° + 60 + x° + 60° + 130° = 360°

2x° + 250° = 360°

2x° = (360 - 250)°

2x° = 110°

x° = 110°

x° = 55°