Saved Bookmarks
| 1. |
In a quantitative determination of iron in an ore, an analyst converted 0.42 g of the ore into its ferrous form . This required 42.00 mL of 0.1 N solution of KMnO_(4) for titration. How many milliequivalents of KMnO_(4) does 42.00 mL of 0.1N solution represent ? |
|
Answer» SOLUTION :In this PROBLEM `Fe^(2+)` is oxidised to `Fe^(3+)` by `KMnO_(4)` (i) m.e of `KMnO_(4)` solution =`0.1 xx42 =4.2 "" ….(Eqn 1)` |
|