Saved Bookmarks
| 1. |
In a quantitative determination of iron in an ore, an analyst converted 0.42 g of the ore into its ferrous form . This required 42.00 mL of 0.1 N solution of KMnO_(4) for titration.How many equivalents of iron were present in the sample of the ore taken for analysis ? |
|
Answer» Solution :In this PROBLEM `FE^(2+)` is oxidised to `Fe^(3+)` by `KMnO_(4)` Equivalent of Fe present in the SAMPLE. ` = ("m.e of"KMnO_(4)"solution")/1000` ...(eqn.3) ` =(4.2)/1000 = 0.0042 ` |
|