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In a quantitative determination of iron in an ore, an analyst converted 0.42 g of the ore into its ferrous form . This required 42.00 mL of 0.1 N solution of KMnO_(4) for titration. What is the percentage of iron in the ore? |
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Answer» SOLUTION :In this PROBLEM `Fe^(2+)` is oxidised to `Fe^(3+)` by `KMnO_(4)` ` % " of iron" = (0.2352)/(0.42) xx 100 = 56.00 % ` |
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