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In a quantitative determination of iron in an ore, an analyst converted 0.42 g of the ore into its ferrous form . This required 42.00 mL of 0.1 N solution of KMnO_(4) for titration. What is the molarity of KMnO_(4) solution used ? |
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Answer» Solution :In this problem `Fe^(2+)` is oxidised to `Fe^(3+)` by `KMnO_(4)` Molarity of `KMnO_(4) = ("normality")/("factor relating mol.wt and eq.wt")` i.e., change in ON ....(Eqn .6i) ` =(0.1)/5 = 0.02 M ` `{UNDERSET(+7)(MnO_(4)^(-))to underset(+2) (MN^(2+))}` |
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