1.

In a radioactive decay, an element ""_(z)X^A emits four alpha- particles, three beta -particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are

Answer»

Z-8, A-13
Z-11, A-16
Z-5, A-13
Z-5, A-16

Solution :After `n_(a), alpha`- DECAYS and `n_(BETA) beta`- decays, the respective atomic number and mass number of resulting nucleus are GIVE by
`Z.=Z-2_(n_(alpha))=Z-8+3=Z-5`
and `A.=A-4n_(alpha)=A-16`


Discussion

No Comment Found

Related InterviewSolutions