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In a reaction, 2A rarr products, the concentration of A decreases from 0.5 "mol L"^(-1) to 0.4 "mol L"^(-1) in 10 minutes. Calculate the rate during this interval ? |
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Answer» Solution :Average rate `=-(1)/(2)(Delta [A])/(Delta L)` `=-(1)/(2)([A]_(2)-[A]_(1))/(t_(2)-t_(1))` `=-(1)/(2)((0.4-0.5)/(10))` `=-(1)/(2)((-0.1)/(10))` `= 0.005 "MOL L"^(-1)"MIN"^(-1)` `= 5xx10^(-3)"M min"^(-1)`. |
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